↧
Answer by user71040 for A Banach space with all Hilbertian subspaces...
There is a basic difference between "all hilbertian are complemented" and "all projections are uniformly bounded". Here is an example: Let $X$ be a separable Banach space such that every operator from...
View ArticleA Banach space with all Hilbertian subspaces complemeneted
Assume that $X$ is a Banach space in which every Hilbertian subspace is complemented (let's say that all the projections are uniformly bounded). What can we say about $X$? It has to be K-convex. By...
View Article
More Pages to Explore .....